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The orbital radius of the Earth (from Earth to Sun) is 1.496 x 10^11 m. Mercury’s orbital radius is 5.79 x 10^10 m and Pluto’s is 5.91
Question
The orbital radius of the Earth (from Earth to Sun) is 1.496 x 10^11 m.
Mercury’s orbital radius is 5.79 x 10^10 m and Pluto’s is 5.91 x 10^12 m.
Calculate the time required for light to travel from the Sun to each of the
three planets.
a. Sun-Earth:_______
b. Sun-Mercury:________
c. Sun-Pluto:________
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Physics
3 years
2021-09-05T15:10:33+00:00
2021-09-05T15:10:33+00:00 1 Answers
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Answers ( )
Explanation:
The orbital radius of the Earth is![Rendered by QuickLaTeX.com r_1=1.496\times 10^{11}\ m](https://documen.tv/wp-content/ql-cache/quicklatex.com-53117e6a60696e7a6c269f5f974c4266_l3.png)
The orbital radius of the Mercury is![Rendered by QuickLaTeX.com r_2=5.79 \times 10^{10}\ m](https://documen.tv/wp-content/ql-cache/quicklatex.com-763ebe1d426151add4a5a7c6b7082e1f_l3.png)
The orbital radius of the Pluto is![Rendered by QuickLaTeX.com r_3=5.91 \times 10^{12}\ m](https://documen.tv/wp-content/ql-cache/quicklatex.com-507ebe676e5fb27f0c4fa3d47a26f45c_l3.png)
We need to find the time required for light to travel from the Sun to each of the three planets.
(a) For Sun -Earth,
Kepler’s third law :
M is mass of sun,![Rendered by QuickLaTeX.com M=1.989\times 10^{30}\ kg](https://documen.tv/wp-content/ql-cache/quicklatex.com-ba722be6824179c02525aae70e23d7ea_l3.png)
So,
(b) For Sun -Mercury,
(c) For Sun-Pluto,