The escape velocity of a rocket from the earth is 11kms^-1. Taking the acceleration due to gravity as 9.8ms^-2, calculate the radius of the

Question

The escape velocity of a rocket from the earth is 11kms^-1. Taking the acceleration due to gravity as 9.8ms^-2, calculate the radius of the earth.

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Thu Giang 5 years 2021-08-06T20:40:07+00:00 1 Answers 267 views 1

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  1. thanhha
    2
    2021-08-06T20:41:52+00:00
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    Answer:

    6.37*10^6 m

    Explanation:

    We know that,

    g = GM/R²

    values given to us

    acceleration due to gravity = g = 9.8 m/s²

    Mass of the earth is= 6.4*10^24

    G = 6.67*10^{-11}

    implementing

    9.8 = 6.67*10^-11 * 6*10^24/R^2

    9.8 = 40.02 * 10^13/ R^2

    R^2 = 4002/98 * 10^12

    R^2 = 40.83* 10^12

    R= 6.37*10^6 m   (approximately)

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