The dwarf planet praamzius is estimated to have a diameter of about 300km and orbits the sun at a distance of 6.4E12m . What is it’s orbital

Question

The dwarf planet praamzius is estimated to have a diameter of about 300km and orbits the sun at a distance of 6.4E12m . What is it’s orbital period in years?

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niczorrrr 5 years 2021-08-10T00:14:13+00:00 1 Answers 67 views 0

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  1. Acacia
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    2021-08-10T00:15:25+00:00
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    Answer:

    Time period of the planet is

    T_2 = 278.7 years

    Explanation:

    As we know by Kepler’s law of time period

    square of time period of planet is proportional to the cube of its orbital radius

    \frac{T_1^2}{T_2^2} = \frac{R_1^3}{R_2^3}

    here we know for Earth

    T_1 = 1 year

    R_1 = 1.5 \times 10^{11} m

    now we have

    \frac{1^2}{T_2^2} = \frac{(1.5 \times 10^{11})^3}{(6.4 \times 10^{12})^3}

    T_2^2 = 7.77 \times 10^4

    T_2 = 278.7 years

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