Suppose you “dig a hole” 52 feet deep and place a baseball machine in the hole, so that the balls fire out at 96 ft /s and land on the groun

Question

Suppose you “dig a hole” 52 feet deep and place a baseball machine in the hole, so that the balls fire out at 96 ft /s and land on the ground outside the hole. What is the velocity of one of these baseballs when it hits the ground?

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Kiệt Gia 5 years 2021-08-06T20:58:45+00:00 1 Answers 88 views 1

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  1. minhkhang
    0
    2021-08-06T21:00:03+00:00
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    Answer:

    76.73 ft/s

    Explanation:

    Let the final velocity is v.

    initial velocity, u = 96 ft/s

    g = 32 ft/s²

    height, h = 52 feet

    use third equation of motion

    v² = u² – 2 gh

    v² = 96 x 96 – 2 x 32 x 52

    v = 76.73 ft/s

    Thus, the speed of the ball as it reaches the ground is 76.73 ft/s.

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