Suppose the current is changing with time according to I = a + bt, where a and b are constants. Determine the magnitude of the emf (in V) th

Question

Suppose the current is changing with time according to I = a + bt, where a and b are constants. Determine the magnitude of the emf (in V) that is induced in the loop if b = 14.0 A/s, h = 1.00 cm, w = 15.0 cm, and L = 1.05 m.

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Acacia 5 years 2021-08-15T09:32:00+00:00 1 Answers 32 views 1

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  1. mit
    1
    2021-08-15T09:33:57+00:00
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    Answer:

    emf=81.51\times 10^{-7} Volt

    Explanation:

    Given that

    I = a + b t

    b = 14 A/s , h= 1 cm , w= 15 cm , L= 1.05 m

    The magnitude of induced emf is given as follows

    emf=\dfrac{d\phi}{dt}

    emf=\dfrac{\mu_o\times L}{2\times \pi}\times ln\dfrac{h+w}{h}\times \dfrac{dI}{dt}

    I = a + b t

    \dfrac{dI}{dt}= b

    Now by putting the values in the above equation we get

    emf=\dfrac{4\times \pi \times 10^{-7}\times 1.05}{2\times \pi}\times ln\dfrac{1+15}{1}\times 14

    emf=81.51\times 10^{-7} Volt

    Thus the induce emf will be

    emf=81.51\times 10^{-7} Volt

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