Suppose​ s(t) is the position of an object moving along a line at time t0. What is the average velocity between the times ta and t​b?

Question

Suppose​ s(t) is the position of an object moving along a line at time t0. What is the average velocity between the times ta and t​b?

in progress 0
Trung Dũng 5 years 2021-07-20T19:24:53+00:00 1 Answers 50 views 0

Answers ( )

    0
    2021-07-20T19:26:04+00:00

    Answer:

    V = \frac{s(t_b) - s(t_a)}{t_b -t_a}

    Explanation:

    Given;

    position of the object as s(t)

    The average velocity is given by;

    V = \frac{s(t_b) - s(t_a)}{t_b -t_a}

    where;

    s(tb) is the object’s final position at time tb

    s(ta) is the initial position of the object at time ta

    tb is the final time of the object’s displacement

    ta is the initial time of the object’s displacement

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )