Suppose 49% of the doctors in America are dentists. If a random sample of size 689 is selected, what is the probability that the proporti

Question

Suppose 49% of the doctors in America are dentists. If a random sample of size 689 is selected, what is the probability that the proportion of doctors who are dentists will be less than 47%

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Neala 5 years 2021-08-03T17:51:48+00:00 1 Answers 26 views 0

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  1. MichaelMet
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    2021-08-03T17:53:40+00:00
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    Answer:

    P(<47\%)=0.1468

    Step-by-step explanation:

    From the question we are told that:

    Percentage of Dentist Doctors P(D)=49\%

    Sample size n=689

    Generally the equation for  probability that the proportion of doctors who are dentists will be less than P(<47\%) is mathematically given by

     P(<47\%)=Z>(\frac{\=x-P(D)}{\sqrt{\frac{P(D)*1-P(D)}{n}}})

     P(<47\%)=Z>(\frac{0.47-0.49}{\sqrt{\frac{0.49*0.51}{689}}})

     P(<47\%)=Z>(1.05)

    Therefore from table

     P(<47\%)=0.1468

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