Question Sofia has 25 coins in nickels and dimes in her pocket for a total of $1.65 how many of each type of coin does she have?

Answer: She has 23 nickels and 5 dimes. Step-by-step explanation: Let n = the number of nickles and d = the number of dimes. The number of each = 28. Set up the equation: n + d = 28 Solve for n: n = 28 – d The total amount is $1.65 or 165 cents: 5n + 10d = 165 Substitute: 5(28 – d) + 10d = 165 140 – 5d + 10d = 165 140 + 5d = 165 5d = 165 – 140 5d = 25 d = 5, the number of dimes. Solve for n: n = 28 – d n = 28 – 5 = 23, the number of nickles. Proof: 5n + 10d = 165 5(23) + 10(5) = 165 115 + 50 = 165 165 = 165 Hope this Helps! Have an Awesome Day!!! <3 Step-by-step explanation: Log in to Reply

Answer: Sofia has 23 nickles & 5 dimes Step-by-step explanation: The number of each is 28 Form an equation: [tex]n+d=28[/tex] Solve for n: [tex]n=28-d[/tex] The total amount is $1.65 for 165 cents: [tex]5n+10d=165[/tex] Substitute: [tex]5(28-d)+10d=165[/tex] [tex]140-5d+10d=165[/tex] [tex]140+5d=165[/tex] [tex]5d=165-140[/tex] [tex]5d=25[/tex] [tex]d=25/5[/tex] [tex]d=5[/tex] Solve for n: [tex]n=28-d[/tex] [tex]n=28-5=23[/tex] ⇒ the number of nickles CHECK: [tex]5n+10d=165[/tex] [tex]5(23)+10(5)=165[/tex] [tex]115+50=165[/tex] [tex]165=165[/tex] hope this helps…. Log in to Reply

Answer:She has 23 nickels and 5 dimes.

Step-by-step explanation:

Let n = the number of nickles and d = the number of dimes.

The number of each = 28. Set up the equation:

n + d = 28

Solve for n:

n = 28 – d

The total amount is $1.65 or 165 cents:

5n + 10d = 165

Substitute:

5(28 – d) + 10d = 165

140 – 5d + 10d = 165

140 + 5d = 165

5d = 165 – 140

5d = 25

d = 5, the number of dimes.

Solve for n:

n = 28 – d

n = 28 – 5 = 23, the number of nickles.

Proof:

5n + 10d = 165

5(23) + 10(5) = 165

115 + 50 = 165

165 = 165

Hope this Helps! Have an Awesome Day!!! <3

Step-by-step explanation:Answer:Sofia has

23 nickles & 5 dimesStep-by-step explanation:The number of each is 28

Form an equation:[tex]n+d=28[/tex]

Solve for n:[tex]n=28-d[/tex]

The total amount is $1.65 for 165 cents:[tex]5n+10d=165[/tex]

Substitute:[tex]5(28-d)+10d=165[/tex]

[tex]140-5d+10d=165[/tex]

[tex]140+5d=165[/tex]

[tex]5d=165-140[/tex]

[tex]5d=25[/tex]

[tex]d=25/5[/tex]

[tex]d=5[/tex]

Solve for n:[tex]n=28-d[/tex]

[tex]n=28-5=23[/tex] ⇒ the number of nickles

CHECK:[tex]5n+10d=165[/tex]

[tex]5(23)+10(5)=165[/tex]

[tex]115+50=165[/tex]

[tex]165=165[/tex]

hope this helps….