Sofia has 25 coins in nickels and dimes in her pocket for a total of $1.65 how many of each type of coin does she have?​

Question

Sofia has 25 coins in nickels and dimes in her pocket for a total of $1.65 how many of each type of coin does she have?​

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Sigridomena 3 years 2021-08-11T05:57:02+00:00 2 Answers 91 views 0

Answers ( )

  1. thongdat2
    0
    2021-08-11T05:58:51+00:00
    Reply

    Answer:

    She has 23 nickels and 5 dimes.

    Step-by-step explanation:

    Let n = the number of nickles and d = the number of dimes.

    The number of each = 28. Set up the equation:

    n + d = 28

    Solve for n:

    n = 28 – d

    The total amount is $1.65 or 165 cents:

    5n + 10d = 165

    Substitute:

    5(28 – d) + 10d = 165

    140 – 5d + 10d = 165

    140 + 5d = 165

    5d = 165 – 140

    5d = 25

    d = 5, the number of dimes.

    Solve for n:

    n = 28 – d

    n = 28 – 5 = 23, the number of nickles.

    Proof:

    5n + 10d = 165

    5(23) + 10(5) = 165

    115 + 50 = 165

    165 = 165

    Hope this Helps! Have an Awesome Day!!! <3

    Step-by-step explanation:

  2. Latifah
    0
    2021-08-11T05:59:00+00:00
    Reply

    Answer:

    Sofia has 23 nickles & 5 dimes

    Step-by-step explanation:

    The number of each is 28

    Form an equation:

    n+d=28

    Solve for n:

    n=28-d

    The total amount is $1.65 for 165 cents:

    5n+10d=165

    Substitute:

    5(28-d)+10d=165

    140-5d+10d=165

    140+5d=165

    5d=165-140

    5d=25

    d=25/5

    d=5

    Solve for n:

    n=28-d

    n=28-5=23 ⇒ the number of nickles

    CHECK:

    5n+10d=165

    5(23)+10(5)=165

    115+50=165

    165=165

    hope this helps….

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