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You want the current amplitude through a 0.450-mH inductor (part of the circuitry for a radio receiver) to be 1.90 mA when a sinusoidal volt
Question
You want the current amplitude through a 0.450-mH inductor (part of the circuitry for a radio receiver) to be 1.90 mA when a sinusoidal voltage with an amplitude of 13.0 V is applied across the inductor.What frequency is required?
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Physics
3 years
2021-08-01T18:50:16+00:00
2021-08-01T18:50:16+00:00 1 Answers
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Answers ( )
Answer:
Frequency required will be 2421.127 kHz
Explanation:
We have given inductance![Rendered by QuickLaTeX.com L=0.450H=0.45\times 10^{-3}H](https://documen.tv/wp-content/ql-cache/quicklatex.com-937d5abe8ade94aeb49b474f9d75b1c5_l3.png)
Current in the inductor![Rendered by QuickLaTeX.com i=1.90mA=1.90\times 10^{-3}A](https://documen.tv/wp-content/ql-cache/quicklatex.com-d1b68059e252de4bb78d52915d0fcc5a_l3.png)
Voltage v = 13 volt
Inductive reactance of the circuit![Rendered by QuickLaTeX.com X_l=\frac{v}{i}](https://documen.tv/wp-content/ql-cache/quicklatex.com-76c4bd3b9688fdaccaac08e3268efacc_l3.png)
We know that
f = 2421.127 kHz