You order 1.5 pounds of turkey at the deli. You will accept the turkey if its weight is between 1.54 and 1.46 pounds. What absolute value in

Question

You order 1.5 pounds of turkey at the deli. You will accept the turkey if its weight is between 1.54 and 1.46 pounds. What absolute value inequality can be used to describe the tolerance of the weight of the turkey?

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Thái Dương 5 years 2021-09-05T05:06:56+00:00 1 Answers 62 views 0

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    2021-09-05T05:08:06+00:00

    Given:

    You order 1.5 pounds of turkey at the deli. You will accept the turkey if its weight is between 1.54 and 1.46 pounds.

    To find:

    The absolute value inequality that can be used to describe the tolerance of the weight of the turkey

    Solution:

    Let x be the actual weight of the turkey.

    It will accepted, if its weight is between 1.54 and 1.46 pounds.

    1.46\leq x\leq 1.54

    Subtract 1.5 from each side.

    1.46-1.5\leq x-1.5\leq 1.54-1.5

    -0.04\leq x-1.5\leq 0.04

    |x-1.5|\leq 0.04

    Therefore, the required absolute inequality is |x-1.5|\leq 0.04.

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