You need to construct a 100 pF capacitor for a science project. You plan to cut two L x L metal squares and insert small spacers between the

Question

You need to construct a 100 pF capacitor for a science project. You plan to cut two L x L metal squares and insert small spacers between their corners. The thinnest spacers you have are 0.20 mm thick. What is the proper value of L?

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Neala 5 years 2021-08-30T00:00:25+00:00 1 Answers 127 views 0

Answers ( )

  1. Nick
    0
    2021-08-30T00:01:49+00:00
    Reply

    Answer:

    value of L = 4.75 cm

    Explanation:

    given data

    capacitor =  100 pF = 100 × 10^{-12} F

    thick = 0.20 mm = 2 × 10^{-4}  m

    solution

    we get here area of each plate that is

    area = L²   …………………..1

    and

    Capacitance, C = εo A ÷ d    ………………2

    put here value so we get

    100 × 10^{-12} = 8.854 × 10^{-12}   × L² ÷  ( 2 × 10^{-4} )

    solve it and we will get

    L =  0.047528 m

    value of L = 4.75 cm

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