You fill a vertical glass tube to a depth of 15.0 cm with freshwater. You then pour on top of the water an additional 15.0 cm of gasoline (d

Question

You fill a vertical glass tube to a depth of 15.0 cm with freshwater. You then pour on top of the water an additional 15.0 cm of gasoline (density 7.40×102kg/m3), which does not mix with water. The upper surface of the gasoline is exposed to the air. Find the gauge pressure at the interface between the gasoline and water.

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Khoii Minh 5 years 2021-07-14T06:02:23+00:00 1 Answers 61 views 0

Answers ( )

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    2021-07-14T06:03:39+00:00

    Answer:

    1087.8 Pa

    Explanation:

    given that:

    You fill a vertical glass tube to a depth of 15.0 cm with freshwater.

    i.e Height (h₁) of the tube = 15.0 cm =0.15 m

    Additional 15.0 cm of gasoline was added  = 0.15 m

    the density of the gasoline \rho_g  = 7.40×10² kg/m³ = 740 kg/m³

    acceleration due to gravity (g) = 9.8 g

    the gauge pressure at the interface between the gasoline and water can be determined as = \rho_g g h

    = 740 × 9.8 × 0.15

    = 1087.8 Pa

    Thus, the gauge pressure at the interface between the gasoline and water =  1087.8 Pa

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