write the equation of a line that is parallel to y = -7/5x + 6 and that passes through the point (2, -6)

Question

write the equation of a line that is parallel to y = -7/5x + 6 and that passes through the point (2, -6)

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Linh Đan 3 years 2021-08-09T14:19:34+00:00 1 Answers 2 views 0

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  1. kimchi2
    0
    2021-08-09T14:20:55+00:00
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    Answer:

    y = -7/5x – 6.7

    Step-by-step

    y = -7/5x + 6. A Line that is parallel will always have the same slope. The slope is m. m in this situation = -7/5x. A lines equation is y = mx + b. m = -7/5. y = -7/5x + b. Now to find b we can substitute the given point which goes through the new line, (2, -6). In this point x =2 and y = -6. Now substitute the x and y values into our equation. y = -7/5x + b is now -6 = -7/5(2) + b. -7/5(2) = -7/10. -6 = 7/10 + b. Subtract 7/10 from -6. Its -6 and 7/10 or -6.7 . -6.7 = b. b = -6.7. Now substitute the b value into the equation. y = -7/5x -6.7.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )