Write the equation of a line that is parallel to y = 3x and goes through (-2, 1).

Question

Write the equation of a line that is parallel to y = 3x and goes through (-2, 1).

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Nick 5 years 2021-08-17T13:35:45+00:00 1 Answers 17 views 0

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  1. Cherry
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    2021-08-17T13:37:16+00:00
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    Answer:

    y = 3x + 7

    Step-by-step explanation:

    If two lines are parallel to each other, they have the same slope.

    The first line is y = 3x. Its slope is 3. A line parallel to this one will also have a slope of 3.

    Plug this value (3) into your standard point-slope equation of y = mx + b.

    y = 3x + b

    To find b, we want to plug in a value that we know is on this line: in this case, it is (-2, 1). Plug in the x and y values into the x and y of the standard equation.

    1 = 3(-2) + b

    To find b, multiply the slope and the input of x (-2)

    1 = -6 + b

    Now, add 6 to both sides to isolate b.

    7 = b

    Plug this into your standard equation.

    y = 3x + 7

    This equation is parallel to your given equation (y = 3x) and contains point (-2, 1)

    Hope this helps!

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )