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Write an equation for a line that is perpendicular to the line 6y – 9x = 12
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Write an equation for a line that is perpendicular to the line 6y – 9x = 12
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Mathematics
4 years
2021-08-31T10:53:05+00:00
2021-08-31T10:53:05+00:00 2 Answers
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Answer:
y = -2/3x + 4
Step-by-step explanation:
first we take the original equation and convert it to y=mx+b (a form we know how to graph)
that gives us y = 3/2x + 2
(Here’s my work for that):
6y – 9x = 12; add 9x on both sides
6y = 9x + 12; divide 6 on both sides
y = 9/6x + 12/6
y = 3/2x + 2
next to make a line *perpendicular* to this, we make the slope negative and swap the fraction (-2/3)
then we just uh graph that slope and try to find the y intercept. i did it already and i got 4
Answer:
Step-by-step explanation:
You need one more piece of information to get a specific line. I’ll get the general one and then we’ll see what comes of it.
Add 9x to both sides.
6y – 9x + 9x = 9x + 12
6y = 9x + 12 Divide by 6
6y/6 = 9x/6 + 12/6
y = 1.5x + 2
Now the perpendicular line must have a slope that is found by using
m1 * m2 = – 1
m1 = 1.5 From the equation above.
1.5 * m2 = – 1 Divide by 1.5
m2 = -1/1.5
m2 = – 2/3
So far what you have is
y = -2/3 x + b You need a value for b. Usually that is found with a point. But I will just call b = 1 since there is nothing else to do
The complete equation becomes
y = -2/3 x + 1
The graph is enclosed.