Write a system of linear inequalities so the points (1, 2) and (4, −3) are solutions of the the system, but the point (−2, 8) is not a solut

Question

Write a system of linear inequalities so the points (1, 2) and (4, −3) are solutions of the the system, but the point (−2, 8) is not a solution to the system.

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Nem 5 months 2021-08-31T06:06:30+00:00 2 Answers 30 views 0

Answers ( )

    0
    2021-08-31T06:07:34+00:00

    Answer:

    y ≤ -5/3x + 11/3

    Step-by-step explanation:

    line pass : (1,2) (4,-3)

    slope (m) = (-3 – 2) / (4 – 1) = – 5/3

    equation: (y-2) / (x-1) = -5/3               y-2 = -5/3x + 5/3

    y = -5/3x + 11/3

    (-2,8) : not solution    y ≤ -5/3x + 11/3

    0
    2021-08-31T06:08:23+00:00

    Answer:

    y < -x + 4

    y < x + 4

    Step-by-step explanation:

    To answer this problem, it is easiest to first plot the three points.

    Then draw two lines that intersect below point (-2, 8) on the y-axis.

    Then find the equations of the two lines, and write two inequalities based on the lines that intersect below the lines.

    y < -x + 4

    y < x + 4

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )