*WILL MARK BRAINLIEST FOR RIGHT ANSWER* How much current must be applied across a 60 Ω light bulb filament in order for it to consume 55 W o

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*WILL MARK BRAINLIEST FOR RIGHT ANSWER* How much current must be applied across a 60 Ω light bulb filament in order for it to consume 55 W of power? Show your work.

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Diễm Kiều 4 months 2021-09-05T15:43:48+00:00 1 Answers 6 views 0

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    2021-09-05T15:45:09+00:00

    Answer: The current must be equal to \frac{\sqrt{33} }{6} amps, or ~0.9574 amps.

    Explanation:

    You can find the current in amperes using ohms and watts from this formula:

    I = \sqrt{\frac{P}{R} }

    Where P represents power in watts, R represents resistance in ohms, and I represents current in amperes.

    You can then substitute 60 and 55 into the equation to find I:

    I = \sqrt{\frac{55}{60} } \\I = \frac{\sqrt{55} }{\sqrt{60} }

    Then, simplify the denominator:

    I = \frac{\sqrt{55} }{2\sqrt{15} }

    Rationalize the denominator:

    I = \frac{\sqrt{55} }{2\sqrt{15} } * \frac{\sqrt{15} }{\sqrt{15} } = \frac{\sqrt{825} }{30}

    Simplify the numerator by finding its factors:

    I = \frac{5\sqrt{33} }{30} = \frac{\sqrt{33} }{6}

    The current must be equal to \frac{\sqrt{33} }{6} amps, or ~0.9574 amps.

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