What volume of 6.49 MHCl is needed to prepare 2.11 L of 1.07 MHCl? Your answer should have three significant figures.

Question

What volume of 6.49 MHCl is needed to prepare 2.11 L of 1.07 MHCl? Your answer should have three significant figures.

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Gia Bảo 5 years 2021-07-25T16:19:44+00:00 1 Answers 31 views 0

Answers ( )

  1. Acacia
    0
    2021-07-25T16:21:09+00:00
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    Answer:

    0.348 L

    Explanation:

    Step 1: Given data

    • Concentration of the concentrated solution (C₁): 6.49 M
    • Volume of the concentrated solution (V₁): ?
    • Concentration of the dilute solution (C₂): 1.07 M
    • Volume of the dilute solution (V₂): 2.11 L

    Step 2: Calculate the volume of the concentrated solution

    We want to prepare a dilute solution from a concentrated one. We can calculate the volume of the concentrated solution using the dilution rule.

    C₁ × V₁ = C₂ × V₂

    V₁ = C₂ × V₂ / C₁

    V₁ = 1.07 M × 2.11 L / 6.49 M = 0.348 L

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