What value of D is required to make vt = 42.7 m/s the terminal velocity of a skydiver of mass 85.0 kg . Express your answer using two signif

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What value of D is required to make vt = 42.7 m/s the terminal velocity of a skydiver of mass 85.0 kg . Express your answer using two significant figures.

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Huyền Thanh 3 years 2021-08-18T23:08:49+00:00 1 Answers 0 views 0

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  1. ThanhThu
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    2021-08-18T23:10:48+00:00
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    Complete Question

    For a human body falling through air  in  a spread edge position , the numerical value of the constant D is about D = 0.2500 kg/m

    What value of D is required to make vt = 42.7 m/s the terminal velocity of a skydiver of mass 85.0 kg . Express your answer using two significant figures?

    Answer:

    The value of D is   D = 0.457 \ kg/m

    Explanation:

    From the question we are told that

         The terminal velocity is  v_t = 42.7 \ m/s

         The mass of the skydiver is  m = 85.0 \ kg

          The numerical value of  D  is  D = 0.2500 kg/m

    From the unit of D  in the question we can evaluate D as  

           D = \frac{m * g }{v^2}

    substituting values  

            D = \frac{85 * 9.8 }{(42.7)^2}

             D = 0.457 \ kg/m

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