What is the volume of 16.0 g of SO2 (g) at STP?

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What is the volume of 16.0 g of SO2 (g) at STP?

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Yến Oanh 5 years 2021-08-27T20:13:52+00:00 1 Answers 19 views 0

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  1. Delwyn
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    2021-08-27T20:15:47+00:00
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    Answer:

    Explanation:

    At STP 1 mole of an ideal gas = 22.4 L.

    Assuming SO2 (sulfur dioxide) acts as an ideal as, we have 16 g SO2 x 1 mol/64 g = 0.25 moles SO2

    0.25 moles x 22.4 L/mole = 5.6 liters

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