What is the size of the force acting on a copper wire with a magnetic flux density of 3.6 x 10-2 T acting at right angles to the wire

Question

What is the size of the force acting on a copper wire with a magnetic flux density of 3.6 x 10-2 T acting at
right angles to the wire of length 24 m and current of C:048 A? Give your answer to an appropriate
number of significant figures.

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Adela 3 years 2021-07-14T01:33:36+00:00 1 Answers 74 views 0

Answers ( )

  1. mit
    0
    2021-07-14T01:35:34+00:00
    Reply

    Answer:

    F = 0.414 N

    Explanation:

    Given that,

    Magnetic flux density,B=3.6\times 10^{-2}\ T

    The length of the wire, l = 24 m

    Current, I = 0.48 A

    We need to find the force acting on the wire. The formula for the force is given by:

    F=ILB

    Put all the values,

    F=0.48\times 24\times 3.6\times 10^{-2}\\\\F=0.414\ N

    So, the force acting on the copper wire is equal to 0.414 N.

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