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## What is the peak intensity β in decibels at a distance of 1 m from the firecracker?

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## Answers ( )

Answer:140dB

Explanation:In this problem you will be using the decibel scale to analyze a small firecracker that emits 1200 of peak power

In order to find to find the peak intensity in dB we must first determine the intensity in W/m^2 that the firecracker is producing:

I= P/(4π)

I= 1200/(4π ) =>96W/m^2

now the intensity in decibels can be calculated by using the dB conversion equation

β= 10log ( )dB

is a reference intensity in the above formula i.e for sound waves and its value is W/m^2

β=10log( )dB => 10log(9.6x )dB

β= 140dB

therefore, at a distance of 1 m from the firecracker the peak intensity β is 140dB

Answer:140 dB

Explanation:β = 10 log (I/I₀)

I=95 Wm⁻²

I₀= 10⁻¹² Wm⁻²