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What is the peak intensity β in decibels at a distance of 1 m from the firecracker?
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Answers ( )
Answer:
140dB
Explanation:
In this problem you will be using the decibel scale to analyze a small firecracker that emits 1200 of peak power
In order to find to find the peak intensity in dB we must first determine the intensity in W/m^2 that the firecracker is producing:
I= P/(4π)
I= 1200/(4π ) =>96W/m^2
now the intensity in decibels can be calculated by using the dB conversion equation
β= 10log ( )dB
is a reference intensity in the above formula i.e for sound waves and its value is W/m^2
β=10log( )dB => 10log(9.6x )dB
β= 140dB
therefore, at a distance of 1 m from the firecracker the peak intensity β is 140dB
Answer:
140 dB
Explanation:
β = 10 log (I/I₀)
I=95 Wm⁻²
I₀= 10⁻¹² Wm⁻²