What is the oxidation number of chromium in K2Cr2O7 ?​

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What is the oxidation number of chromium in K2Cr2O7 ?​

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Dulcie 3 years 2021-08-30T01:36:39+00:00 1 Answers 6 views 0

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  1. thanhha
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    2021-08-30T01:37:44+00:00
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    Answer:

    +6 per Cr molecule, +12 overall.

    Explanation:

    Refer to a oxidation table, where O usually has an oxidation # of -2 (unless it’s H2O2, where it’s -1). We have 7 molecules of Oxygen, so we have a total of -14 on Oxygen. We also know group 1 metals all have an oxidation # of +1 so we can say potassium (K) has an oxidation # of +1 per molecule, +2 overall.

    Before we determine Cr let’s check what the overall charge is, in this compound its 0 (neutral), so we just Cr to help K balance out the -14 charge on Oxygen. We can look at like this.

    14= x +2

    Where x is Chromium.

    14 -2 = 12

    So Chromium will have a +12 charge but we have 2 molecules, so each Chromium will have a +6 charge.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )