What is the number of moles in 125ml of 0.25 M NaNO3solution?

Question

What is the number of moles in 125ml of 0.25 M NaNO3solution?

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Thu Nguyệt 5 years 2021-07-11T11:12:13+00:00 1 Answers 17 views 0

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  1. quangkhai
    0
    2021-07-11T11:13:20+00:00
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    Answer:

    0.0313 mole.

    Explanation:

    From the question given above, the following data were obtained:

    Volume of solution = 125 mL

    Molarity of NaNO₃ = 0.25 M

    Number of mole of NaNO₃ =?

    Next, we shall convert 125 mL to litre (L). This can be obtained as follow:

    1000 mL = 1 L

    Therefore,

    125 mL = 125 mL × 1 L / 1000 mL

    125 mL = 0.125 L

    Thus, 125 mL is equivalent to 0.125 L.

    Finally, we shall determine the number of mole of NaNO₃ in the solution. This can be obtained as follow:

    Volume of solution = 0.125 L.

    Molarity of NaNO₃ = 0.25 M

    Number of mole of NaNO₃ =?

    Molarity = mole / Volume

    0.25 = mole of NaNO₃ / 0.125

    Cross multiply

    Mole of NaNO₃ = 0.25 × 0.125

    Mole of NaNO₃ = 0.0313 mole.

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