what is the length of the major axis of the conic section (x+2)^2/64+(y-1)^2/81=1

Question

what is the length of the major axis of the conic section (x+2)^2/64+(y-1)^2/81=1

in progress 0
Thu Giang 3 years 2021-08-15T16:58:46+00:00 1 Answers 10 views 0

Answers ( )

    0
    2021-08-15T17:00:19+00:00

    Answer: The length of the major axis = 18 units.

    Step-by-step explanation:

    For equation ellipse: \dfrac{(x-a)^2}{m^2}+\dfrac{(y-b)^2}{n^2}=1

    If n>m , then length of major axis = 2n

    Otherwise 2m

    Given equation:

    \dfrac{(x+2)^2}{64}+\dfrac{(y-1)^2}{81}=1\ \text{ ,which is an ellipse.}\\\\\Rightarrow\ \dfrac{(x+2)^2}{8^2}+\dfrac{(y-1)^2}{9^2}=1

    9>8

    So, the length of the major axis = 2(9) = 18 units.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )