what is the Ka of a 0.0592 M solution of hydrofluoric acid (HF) with a pH of 6.90

Question

what is the Ka of a 0.0592 M solution of hydrofluoric acid (HF) with a pH of 6.90

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Gia Bảo 4 years 2021-09-05T03:56:55+00:00 2 Answers 21 views 0

Answers ( )

  1. Latifah
    0
    2021-09-05T03:58:42+00:00
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    Answer: 2.7 x 10^-13

    Explanation:

  2. thienhuong
    0
    2021-09-05T03:58:46+00:00
    Reply

    Answer:

    2.7*10^-13

    coefficient= 2.7

    exponent= -13

    Explanation:

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )