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What is the index for a type of oil if light has a velocity of 2.5 x 10^(8) m/s in this substance?
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Answers ( )
Answer:
1.2
Explanation:
Data obtained from the question include:
Velocity of light in the oil (V) = 2.5×10^8m/s
Velocity of light in air (C) = 3×10^8m/s
Refractive Index (n) =.?
The rafractive index (n) for the oil is given by:
Rafractive index (n) = Velocity in air (V) /velocity in oil (V)
n = C/V
n = 3×10^8 / 2.5×10^8
n = 1.2
Therefore, the Refractive Index of the oil is 1.2.