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## What is the equation of a line that is parallel to 2x +3y = 3 and passes through the point (3, -4) ?

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What is the equation of a line that is parallel to 2x +3y = 3 and passes through the point (3, -4) ?

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Mathematics
1 year
2021-08-26T04:56:31+00:00
2021-08-26T04:56:31+00:00 1 Answers
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## Answers ( )

Answer:2x + 3y = -6

Step-by-step explanation:The equation of the new line will be identical to that of the given line except that the constant term will differ.

Start with the given 2x + 3y = 3 and replace x with 3 and y with -4. We get:

2(3) + 3(-4) = C, and C = 6 – 12 = -6

The equation of the new line is therefore

2x + 3y = -6