What is the equation of a line that is parallel to 2x +3y = 3 and passes through the point (3, -4) ?

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What is the equation of a line that is parallel to 2x +3y = 3 and passes through the point (3, -4) ?

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Xavia 3 weeks 2021-08-26T04:56:31+00:00 1 Answers 0 views 0

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    2021-08-26T04:57:43+00:00

    Answer:

    2x + 3y = -6

    Step-by-step explanation:

    The equation of the new line will be identical to that of the given line except that the constant term will differ.

    Start with the given 2x + 3y = 3 and replace x with 3 and y with -4.  We get:

    2(3) + 3(-4) = C, and C = 6 – 12 = -6

    The equation of the new line is therefore 2x + 3y = -6

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