What is the equation in slope-intercept form of the line that crosses the x-axis at 12 and is perpendicular to the line represented by y = 6

Question

What is the equation in slope-intercept form of the line that crosses the x-axis at 12 and is perpendicular to the line represented by y = 6/5x + 9 ?

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Kim Chi 5 years 2021-09-05T01:59:19+00:00 1 Answers 24 views 0

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  1. Acacia
    0
    2021-09-05T02:00:23+00:00
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    Answer:

    The equation of the line in slope-intercept form is;

    y = 10 – 5/6·x

    Step-by-step explanation:

    The given equation of the line to which the required line is perpendicular is presented as follows;

    y = 6/5·x + 9

    A point on the desired line = (12, 0)  

    The relationship of the slope, m₁ of a line, perpendicular to the another line of slope m₂, is given as follows;

    m₁  = -1/m₂

    Therefore;

    The slope of the desired line = -1/(The slope of the given line)

    The slope of the desired line = -1/(6/5) = -5/6

    The equation of the desired line in point and slope form is given as follows;

    y – 0 = -5/6 × (x – 12)

    Therefore, the equation of the line in slope-intercept form is;

    y = -5/6·x + 10 = 10 – 5/6·x.

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