What is the domain and range of It’s h(x)= -1/2(x-4)^2 +3

Question

What is the domain and range of It’s
h(x)= -1/2(x-4)^2 +3

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Huyền Thanh 5 years 2021-07-26T02:58:33+00:00 1 Answers 11 views 0

Answers ( )

  1. RobertKer
    0
    2021-07-26T02:59:42+00:00
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    Answer:

    Domain:  [
    −
    3
    ,∞
    )

    Range:  (
    −
    ∞
    ,
    0
    ]

    Step-by-step explanation:

    h
    (
    x
    )
    =
    −
    √
    x
    +
    3  

    the domain:

    x
    +3
    ≥
    0  x
    ≥
    −
    3  

    in interval form:

    [
    −
    3
    ,
    ∞
    )  

    the range:

    lowest possible value under the square root sign is zero, thus:

    y
    ≤
    0  

    in the interval form:

    (
    −
    ∞
    ,
    0
    ]

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )