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What is the diameter of a sphere with a volume of 18174 ft^3 to the nearest tenth of a foot?
Question
What is the diameter of a sphere with a volume of 18174 ft^3 to the nearest tenth of a foot?
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Mathematics
4 years
2021-07-19T03:47:12+00:00
2021-07-19T03:47:12+00:00 1 Answers
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Answers ( )
Answer:
Diameter = 33 feet
Step-by-step explanation:
Diameter = 2 x radius
Given that the volume = 18174
, then;
Volume of sphere =
[tex]\pi[/tex]
where r is the radius of the sphere.
Thus,
18174 =
x
x 
=

18174 x 21 = 88
381654 = 88
= 4336.9773
r =![Rendered by QuickLaTeX.com \sqrt[3]{4336.9773}](https://documen.tv/wp-content/ql-cache/quicklatex.com-10074ac8c0a2e6fc9cc33c72198d30a6_l3.png)
r = 16.3078
The diameter of the sphere = 2 x 16.3078
= 32.6156
= 33 feet