What is the diameter of a sphere with a volume of 18174 ft^3 to the nearest tenth of a foot?

Question

What is the diameter of a sphere with a volume of 18174 ft^3 to the nearest tenth of a foot?

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King 4 years 2021-07-19T03:47:12+00:00 1 Answers 32 views 0

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    2021-07-19T03:49:11+00:00

    Answer:

    Diameter = 33 feet

    Step-by-step explanation:

    Diameter = 2 x radius

    Given that the volume = 18174 ft^{3}, then;

    Volume of sphere = \frac{4}{3}[tex]\pi[/tex]r^{3}

    where r is the radius of the sphere.

    Thus,

    18174 = \frac{4}{3} x \frac{22}{7} x r^{3}

             = \frac{88}{21} r^{3}

    18174 x 21 = 88 r^{3}

    381654 = 88 r^{3}

    r^{3} = \frac{381654}{88}

       = 4336.9773

    r = \sqrt[3]{4336.9773}

    r = 16.3078

    The diameter of the sphere = 2 x 16.3078

                                                  = 32.6156

                                                  = 33 feet

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