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What is the center of the circle for this equation: (x – 6)² + (y + 9)² = 25
Question
What is the center of the circle for this equation:
(x – 6)² + (y + 9)² = 25
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Mathematics
3 years
2021-08-21T20:00:30+00:00
2021-08-21T20:00:30+00:00 1 Answers
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Answers ( )
Answer:
Step-by-step explanation:
Knowing this information, we can deduce that the center of the circle is at
(
6
,
−
2
)
, and the radius measures 3 units.
x
=
9
is a vertical line, while the circle will extend equal length in all direction, in function of it’s radius. Looking at the centre and adding 3 to the x value, we get the point
(
9
,
−
2
)
. This point doesn’t only lie on the circle; it also lies on the line
x
=
9
. Furthermore, this is the furthest possible distance from the center, so the line will only pass through this one point. Therefore, we can state that the line x = 9 is tangent to
(
x
−
6
)
2
+
(
y
+
2
)
2
=
9
If you graph the circle and the line you will get the same answer.