What average force is required to stop a 1400 kg car in 8.0 s if the car is traveling at 95 km/h?

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Physics Nick 5 years 2021-07-16T12:53:57+00:00 2021-07-16T12:53:57+00:00 1 Answers 21 views 0

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Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

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Nem · Answer 1 · 2021-07-16T12:55:56+00:00

Nem

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2021-07-16T12:55:56+00:00 July 16, 2021 at 12:55 pm

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Answer: -424.24 N

It’s negative because the vehicle is in motion and we want to bring it to a full stop, therefore we must apply a force in the opposite direction.

Explanation:

$F = ma\\\\F = Force\\m = mass (kg)\\a = acceleration (m/s^2)$

Find the acceleration

$V_1 = 95km/h\\V_2 = 0$

Convert from km/h to m/s

$95\frac{km}{h} (\frac{1000m}{1km} )(\frac{1h}{3600s} )= 26.39m/s$

$a = \frac{V_2-V_1}{t}\\\\a = \frac{0-26.39m/s }{8s}\\\\a = -3.30m/s^2$

Plug this information into the original Force Formula

$F =ma\\\\F = (1400kg)(-3.30m/s^2)\\F =-424.24 N$