Using the following reaction: H2SO4 (aq) + 2NaOH (aq) → Na2SO4 (aq) + 2H2O (l) Calculate the molarity of the

Question

Using the following reaction:

H2SO4 (aq) + 2NaOH (aq) → Na2SO4 (aq) + 2H2O (l)

Calculate the molarity of the H2SO4 solution if 14.92 mL of NaOH was necessary to reach the endpoint of a titration. The molarity of the NaOH solution was 0.83 M and 25.18 mL of H2SO4 was added to the Erlenmeyer flask.

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Orla Orla 5 years 2021-07-11T06:07:23+00:00 1 Answers 42 views 0

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  1. Eirian
    0
    2021-07-11T06:09:17+00:00
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    Answer:

    The molar concentration of the H₂SO₄ solution is 0.28 M

    Explanation:

    Molar concentration = number of moles / volume in litres

    Number of moles = molar concentration × volume

    From the equation of reaction, molar ratio of acid to base = 1 : 2

    Using the formula; Na/Nb = CaVa/CbVb

    Where Na is the number of moles of acid; Nb = number of moles of base; Ca = concentration of acid; Va = volume of acid; Cb = concentration of base; Vb = volume of base; Na/Nb = mole ratio of acid to base

    Substituting the given values in the equation:

    1/2 = Ca × 25.18 / 0.93 × 14.92

    Ca = 0.93 × 14.92/ 25.18 × 2

    Ca = 0.28M

    Therefore, the molar concentration of the H₂SO₄ solution is 0.28 M

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )