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Using the following equation how many grams of water you would get from 886 g of glucose: C6H12O6 + 6O2 → 6CO2 + 6H2O + energy
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Answer:
531.6g
Explanation:
Total moles of glucose in this case is: 886/180= 4.922 (mole)
For every 1 mole glucose we get 6 mole water
-> Mole of water is: 4.922 * 6= 29.533 (mole)
weight of water is 18. Therefore, total weight of water that we will have from 886g of glucose are: 25.933*18= 531.6g