Two vertical posts stand side by side. One post is 8 feet tall while the other is 17 feet tall. If a 24 foot wire is stretched between the t

Question

Two vertical posts stand side by side. One post is 8 feet tall while the other is 17 feet tall. If a 24 foot wire is stretched between the tops of the posts, how far apart are the posts?​

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Khoii Minh 5 years 2021-09-04T19:48:44+00:00 2 Answers 16 views 0

Answers ( )

  1. diemthu
    0
    2021-09-04T19:50:11+00:00
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    Answer:

    22 1/4 feet

    Step-by-step explanation:

    you can sketch this problem to be a right triangle with a hypotenuse of 24 feet and one leg of 9 feet (17 – 8).

    use Pythagorean Theorem to find the base side, which represents the distance between the posts

    a² + 9² = 24²

    a² + 81 = 576

    a² = 576 – 81

    a² = 495

    a = \sqrt{495}

    a = \sqrt{9} · \sqrt{55}  =  3\sqrt{55}, which is approx 22.25

  2. thongdat2
    0
    2021-09-04T19:50:20+00:00
    Reply

    Answer:

    about 22.25 feet

    Step-by-step explanation:

    You can think of it like a triangle, which you can see at the bottom

    Then, use the pythagorean theorem, a^2 + b^2 = c^2.

    you have a = 9 and c = 24, so

    9^2 + b^2 = 24^2\\81 + b^2 = 576\\b^2 = 495\\b = \sqrt{495} = 3\sqrt{55} = about 22.25

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