Two tiny conducting spheres are identical and carry charges of -22.0 µC and +46.0 µC. They are separated by a distance of 2.47 cm. (a) What

Question

Two tiny conducting spheres are identical and carry charges of -22.0 µC and +46.0 µC. They are separated by a distance of 2.47 cm. (a) What is the magnitude of the force that each sphere experiences, and is the force attractive or repulsive?

in progress 0
Gia Bảo 3 years 2021-07-26T17:20:04+00:00 1 Answers 30 views 0

Answers ( )

    0
    2021-07-26T17:21:04+00:00

    Explanation:

    Given that,

    Charge 1, q_1=-22\ \mu C

    Charge 2, q_2=+46\ \mu C

    Separation between spheres, d = 2.47 cm

    We need to find the magnitude of the force that each sphere experiences. It is given by the formula as follows :

    F=k\dfrac{q_1q_2}{d^2}\\\\F=9\times 10^9\times \dfrac{22\times 10^{-6}\times 46\times 10^{-6}}{(2.47\times 10^{-2})^2} \\\\F=14928.94\ N\\\\F=1.49\times 10^4\ N

    As the two charges have opposite sign, the force between them is attractive.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )