Two tiny conducting spheres are identical and carry charges of -22.0 µC and +46.0 µC. They are separated by a distance of 2.47 cm. (a) What

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Two tiny conducting spheres are identical and carry charges of -22.0 µC and +46.0 µC. They are separated by a distance of 2.47 cm. (a) What is the magnitude of the force that each sphere experiences, and is the force attractive or repulsive?

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Gia Bảo 4 years 2021-07-26T17:20:04+00:00 1 Answers 33 views 0

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  1. thienan
    0
    2021-07-26T17:21:04+00:00
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    Explanation:

    Given that,

    Charge 1, q_1=-22\ \mu C

    Charge 2, q_2=+46\ \mu C

    Separation between spheres, d = 2.47 cm

    We need to find the magnitude of the force that each sphere experiences. It is given by the formula as follows :

    F=k\dfrac{q_1q_2}{d^2}\\\\F=9\times 10^9\times \dfrac{22\times 10^{-6}\times 46\times 10^{-6}}{(2.47\times 10^{-2})^2} \\\\F=14928.94\ N\\\\F=1.49\times 10^4\ N

    As the two charges have opposite sign, the force between them is attractive.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )