Two particles that have the same mass m = 500 g are connected by a massless cord of � = 30 cm and rotate around O with angular speed ω = 2.

Question

Two particles that have the same mass m = 500 g are connected by a massless cord of � = 30 cm and rotate around O with angular speed ω = 2.0 rev/s. What is the angular momentum of the system?

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Dâu 5 years 2021-08-05T04:52:08+00:00 1 Answers 24 views 0

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  1. Cherry
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    2021-08-05T04:54:06+00:00
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    Answer:

    The angular momentum of the system is 0.18kgm²/s

    Explanation:

    L = angular momentum of the particle 1 + angular momentum of the particle 2

    L = ml²ω + ml²ω

    L = 2ml²ω

    Given that,

    m = 500g are connected by a massless cord

       =0.500kg

    l = 30cm

     = 0.30m

    angular speed ω = 2.0 rev/s

    angular momentum of the system =

    L = 2ml²ω

    L = 2 × 0.500 × (0.30)² × 2

    L = 2 × 0.500 × 0.09 × 2

    L = 0.18kgm²/s

    Thus, the angular momentum of the system is 0.18kgm²/s

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