Two parallel copper rods supply power to a high-energy experiment, carrying the same current in opposite directions. The rods are held 8.0 c

Question

Two parallel copper rods supply power to a high-energy experiment, carrying the same current in opposite directions. The rods are held 8.0 cm apart by insulating blocks mounted every 1.5 m. If each block can tolerate a maximum tension force of 200 N, what is the maximum allowable current

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Diễm Thu 5 years 2021-08-16T01:07:53+00:00 1 Answers 12 views 0

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  1. sori
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    2021-08-16T01:09:09+00:00
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    Answer:

    the maximum allowable current is 7302.967  amperl

    Explanation:

    The computation of the maximum allowable current is shown below;

    Force F = mean ÷ 4π 2 I_1 I_2 ÷d  × ΔL

    200 N = (10)^-7 (2I × I) ÷ 0.08 × 1.5

    200 = 3.75 × 10^-6 I^2

    I = √200 ÷ √ 3.75 × 10^-6

    = 7302.967  amperl

    Hence, the maximum allowable current is 7302.967  amperl

    Basically we applied the above formula

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