Two objects collide elastically. The first has a mass of 5.00kg and a velocity of 8.00 m/s. The second has a mass of 2.50 kg and a vel

Question

Two objects collide elastically. The first has a mass of 5.00kg and a
velocity of 8.00 m/s. The second has a mass of 2.50 kg and a velocity
of -4.00m/s. If the velocity of object 1 after the collision is -4.00m/s,
what is the velocity of object 2?

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RuslanHeatt 3 years 2021-09-02T07:32:32+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-09-02T07:33:55+00:00

    Answer:

    Explanation:

    General formula

    m1 * vi + m2*v2 = m1*v3 + m2*v4

    Givens

    m1 = 5

    m2 = 2.5

    v1 = 8 m/s

    v2 = – 4 m/s

    v3 = -4 m/s

    v4 = x

    Solution

    5 * 8 – 2.5 * 4 = 5 * -4 + 2.5*x

    40 – 10 = -20 + 2.5x

    30 = – 20 + 2.5x

    50 = 2.5x

    x = 50/2.5

    x = 20 m/s in the positive direction

    Remark

    Does this answer make sense? It should. You have 5 kg moving 8m/s in the plus direction. That’s a lot of momentum. In addition after the collision, it turns around which is more momentum needed.

    It has to give up that extra momentum to the 2.5 kg mass.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )