Two loops of wire are arranged so that a changing current in one will induce a current in the other. If the current in the first is increasi

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Two loops of wire are arranged so that a changing current in one will induce a current in the other. If the current in the first is increasing clockwise by one amp every second, the current in the second loop will

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Vodka 4 years 2021-07-23T10:43:00+00:00 1 Answers 27 views 0

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  1. Adela
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    2021-07-23T10:44:27+00:00
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    Answer:

    The current in the second loop will stay constant

    Explanation:

    Since the induced emf in the second coil, ε due to the changing current i₁ in the first wire loop ε = -Mdi₁/dt where M = mutual inductance of the coils and di₁/dt = rate of change of current in the first coil = + 1 A/s (positive since it is clockwise)

    Now ε = i₂R where i₂ = current in second wire loop and R = resistance of second wire loop.

    So,  i₂R = -Mdi₁/dt

    i₂ = -Mdi₁/dt/R

    Since di₁/dt = + 1 A/s,

    i₂ = -Mdi₁/dt/R

    i₂ = -M × + 1 A/s/R

    i₂ = -M/R

    Since M and R are constant, this implies that i₂ = constant

    So, the current in the second wire loop will stay constant.

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