Two long, straight wires are parallel and 10 cm apart. One carries a current of 2.0 A, the other a current of 5.0 A. What is the magnitude a

Question

Two long, straight wires are parallel and 10 cm apart. One carries a current of 2.0 A, the other a current of 5.0 A. What is the magnitude and direction of the force per unit length exerted by the first wire on the second wire if the currents flow in the same direction?

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Minh Khuê 6 months 2021-08-17T07:27:23+00:00 1 Answers 10 views 0

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    2021-08-17T07:28:44+00:00

    Answer:

    2\times 10^{-5}N/m and attractive(towards to each other)

    Explanation:

    We are given that

    Distance between wires,d=10 cm=10\times 10^{-2} m

    1 m=100 cm

    I_1=2 A

    I_2=5 A

    We have to find the magnitude and direction of the force per unit length exerted by the first wire on the second wire if the currents flow in the same direction.

    We know that magnetic force per unit length

    \frac{F}{l}=\frac{2\mu_0I_1I_2}{4\pi d}

    Where \frac{\mu_0}{4\pi}=10^{-7}

    Using the formula

    \frac{F}{l}=\frac{2\times 10^{-7}\times 2\times 5}{10\times 10^{-2}}

    \frac{F}{l}=2\times 10^{-5}N/m

    When the wires carrying current in same direction then the force between the wires attract to each other.

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