Two identical speakers separated by 14.9 m are driven by the same oscillation with a frequency of 26.3 Hz. x y b (x, y) b 1 st A 2 nd 14.9 m

Question

Two identical speakers separated by 14.9 m are driven by the same oscillation with a frequency of 26.3 Hz. x y b (x, y) b 1 st A 2 nd 14.9 m Find the distance from the first speaker to a receiver at A if it records a minimum in sound intensity. Take the speed of sound to be 344.1 m/s

in progress 0
Edana Edana 5 years 2021-08-14T22:49:08+00:00 1 Answers 23 views 0

Answers ( )

  1. vankhanh
    0
    2021-08-14T22:50:25+00:00
    Reply

    Answer:

    Explanation:

    Given that,

    Distance between two speakers

    d=14.9m

    Frequency =26.3Hz

    Speed of sound V=344.1m/s

    Formula to calculate path difference is given as

    d1-d2=λ/2

    Where d1= distance from the first speaker

    d2=distance from the second speaker

    So let the minimum intensity be at x

    Distance of the first speaker from A is x m

    Distance of the second speaker from A is (14.9-x)m

    The wavelength is given as

    V=fλ

    λ=V/f

    λ=344.1/26.3

    λ=13.1m

    Using the equation.

    d1-d2=λ/2

    x-(14.9-x)=13.1/2

    x-14.9+x=6.54

    2x=6.54+14.9

    2x=21.44

    x=21.44/2

    x=10.72m

    The minimum sound intensity can be record at a distance of 10.72m from first speaker

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )