Two cars honking at the same frequency of 800 Hz are moving toward a pedestrian standing at the curb. One car is moving with speed 25 m/s, a

Question

Two cars honking at the same frequency of 800 Hz are moving toward a pedestrian standing at the curb. One car is moving with speed 25 m/s, and the second car is moving at 21 m/s. What is the frequency of the beats heard by the pedestrian? Take the speed of sound as 343 m/s.

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Ladonna 5 months 2021-08-15T03:44:07+00:00 1 Answers 2 views 0

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  1. Delwyn
    0
    2021-08-15T03:45:35+00:00
    Reply

    Answer:

    The frequency of the beats heard by the pedestrian is 9.33 Hz

    Explanation:

    Frequency of the two cars, F = 800 Hz

    speed of sound in air, V = 343 m/s

    The sound wave length, λ = ?

    λ = V / F

    λ = 343 / 800

    λ = 0.42875 m

    The frequency of the car moving at 25 m/s heard by the pedestrian

    f₁ = v₁ / λ

    f₁ = 25 / 0.42875

    f₁ = 58.31 Hz

    The frequency of the car moving at 21 m/s heard by the pedestrian

    f₂ = v₂ / λ

    f₂ = 21 / 0.42875

    f₂ = 48.98 Hz

    The beat frequency  = f₁ – f₂

                                      = 58.31 – 48.98

                                      = 9.33 Hz

    Therefore, the frequency of the beats heard by the pedestrian is 9.33 Hz

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