Two boys are sliding toward each other on a frictionless, ice-covered parking lot. Jacob, mass 45 kg, is gliding to the right at 8.08 m/s, a

Question

Two boys are sliding toward each other on a frictionless, ice-covered parking lot. Jacob, mass 45 kg, is gliding to the right at 8.08 m/s, and Ethan, mass 31.0 kg, is gliding to the left at 10.9 m/s along the same line. When they meet, they grab each other and hang on.(a) What is their velocity immediately thereafter?

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Helga 3 years 2021-08-16T22:05:03+00:00 1 Answers 15 views 0

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  1. Sapo1
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    2021-08-16T22:06:46+00:00
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    Answer:

    v=0.3381\ m.s^{-1} in the direction of motion of Jacob

    Explanation:

    Given:

    mass  of Jacob, m_j=45\ kg

    velocity of Jacob, v_j=8.08\ m.s^{-1}

    mass of Ethan, m_e=31\ kg

    velocity of Ethan, v_e=10.9\ m.s^{-1}

    Now using the conservation of linear momentum for the case:

    (When the two masses in motion combine to form one after the collision then they will move together in the direction of the greater momentum.)

    (m_j+m_e).v=m_j.v_j-m_e.v_e

    (45+31)\times v=45\times 8.08-31\times 10.9

    v=0.3381\ m.s^{-1} in the direction of motion of Jacob as it was assumed to be positive.

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