Two boxes connected by a light horizontal rope are on a horizontal surface. The coefficient of kinetic fric-tion between each box and the su

Question

Two boxes connected by a light horizontal rope are on a horizontal surface. The coefficient of kinetic fric-tion between each box and the surface is ilk = 0.30. Box B has mass 5.00 kg, and box A has mass m. A force F with magnitude 40.0 N and direction 53.1° above the horizontal is applied to the 5.00-kg box, and both boxes move to the right with a = 1.50 m/s2. A) What is the tension T in the rope that connects the boxes? B) What is m?

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Hải Đăng 5 years 2021-09-03T05:22:57+00:00 1 Answers 24 views 0

Answers ( )

  1. linhdan
    0
    2021-09-03T05:24:29+00:00
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    Answer:

    (A). The tension in the rope that connects the boxes is 10.50 N.

    (B). The value of m is 7 kg.

    Explanation:

    Given that,

    Mass of box B = 5.00 kg

    Mass of box A = m

    Force = 40.0 N

    Direction= 53.1°

    Acceleration = 1.50 m/s²

    Coefficient of kinetic friction = 0.30

    (A). We need to calculate the tension in the rope that connects the boxes

    Using balance equation

    T=ma+m\cos\theta

    Put the value into the formula

    T=5\times1.50+5.00\cos53.1

    T=10.50\ N

    (B). We need to calculate the value of m

    Using formula of tension

    T=ma

    m=\dfrac{T}{a}

    Put the value into the formula

    m=\dfrac{10.50}{1.50}

    m=7\ kg

    Hence, (A). The tension in the rope that connects the boxes is 10.50 N.

    (B). The value of m is 7 kg.

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