Two blocks with different masses are attached to either end of a light rope that passes over a light, frictionless pulley suspended from the

Question

Two blocks with different masses are attached to either end of a light rope that passes over a light, frictionless pulley suspended from the ceiling. The masses are released from rest, and the more massive one starts to descend. After this block has descended 1.20 m, its speed is 3.00 m/s.

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Thạch Thảo 3 years 2021-08-13T18:31:26+00:00 1 Answers 16 views 0

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  1. Edana
    0
    2021-08-13T18:32:31+00:00
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    Answer with Explanation:

    We are given that

    Speed,v=3 m/s

    y=1.2 m

    Total mass of two block=M=m_1+m_2=22 kg

    We have to find the mass of each block.

    According to law of conservation of energy

    \Delta K=\Delta U

    \frac{1}{2}(m_1+m_2)v^2=(m_2-m_1)gy

    \frac{1}{2}(22)(3)^2=(m_2-m_1)\times 9.8\times 1.2

    Where g=9.8 m/s^2

    m_2-m_1=\frac{22\times 3^2}{2\times 9.8\times 1.2}

    m_2-m_1=8.4

    m_2+m_1=22

    2m_2==30.4

    m_2=\frac{30.4}{2}=15.2 kg

    Substitute the value

    m_1+m_2=22

    m_1+15.2=22

    m_1=22-15.2

    m_1=6.8 kg

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