To throw the discus, the thrower holds it with a fully outstretched arm. Starting from rest, he begins to turn with a constant angular accel

Question

To throw the discus, the thrower holds it with a fully outstretched arm. Starting from rest, he begins to turn with a constant angular acceleration, releasing the discus after making one complete revolution. The diameter of the circle in which the discus moves is about 1.6 mm.
If the thrower takes 1.0 s to complete one revolution, starting from rest, what will be the speed of the discus at release?

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Thiên Ân 3 years 2021-08-12T19:01:33+00:00 1 Answers 16 views 0

Answers ( )

  1. MichaelMet
    0
    2021-08-12T19:02:52+00:00
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    Answer:

    Explanation:

    Time taken to complete one revolution is called time period.

    So, Time period, T = 1 s

    Diameter = 1.6 mm

    radius, r = 0.8 mm

    Let the angular speed is ω.

    The relation between angular velocity and the time period is

    \omega =\frac{2\pi}{T}

    ω = 2 x 3.14 = 6.28 rad/s

    The relation between the linear velocity and the angular velocity is

    v = r x ω

    v = 0.8 x 10^-3 x 6.28

    v = 0.005 m/s

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