To take off from the ground, an airplane must reach a sufficiently high speed. The velocity required for the takeoff, the takeoff velocity,

Question

To take off from the ground, an airplane must reach a sufficiently high speed. The velocity required for the takeoff, the takeoff velocity, depends on several factors, including the weight of the aircraft and the wind velocity. Part A A plane accelerates from rest at a constant rate of 5.00 m/s2 along a runway that is 1800 m long. Assume that the plane reaches the required takeoff velocity at the end of the runway. What is the time tTO needed to take off

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Khang Minh 5 years 2021-08-06T01:44:16+00:00 1 Answers 46 views 0

Answers ( )

  1. Nho
    0
    2021-08-06T01:45:55+00:00
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    Answer:

    t = 26.8 s

    Explanation:

    Here, we can use the second equation of motion to calculate the required time:

    s = v_it + \frac{1}{2}at^2

    where,

    s = distance = 1800 m

    vi = initial speed = 0 m/s

    t = time needed = ?

    a = acceleration = 5 m/s²

    Therefore,

    1800\ m = (0\ m/s)t+\frac{1}{2}(5\ m/s^2)t^2\\\\t^2 = \frac{(1800\ m)(2)}{5\ m/s^2}\\\\t = \sqrt{720\ s^2}

    t = 26.8 s

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