To find the distance AB across a river, a distance BC of 415 m is laid off on one side of the river. It is found that B = 112.2° and C = 18.

Question

To find the distance AB across a river, a distance BC of 415 m is laid off on one side of the river. It is found that B = 112.2° and C = 18.3°. Find AB.

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Amity 3 years 2021-07-21T12:01:41+00:00 1 Answers 148 views 0

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  1. King
    0
    2021-07-21T12:02:52+00:00
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    Answer:

    91.87

    Step-by-step explanation:

    We are given that BC=361m, Angle B= 111 °20'=111+\frac{20}{60} = 111.33 degrees,     1 degrees = 60 minutes, Angle C= 12 °  15′ = 12 + \frac{15}{60} = 12.25 degrees, We have to find the value of AB, the Sum of angles of triangle=180 degrees, ⦟A + ⦟B + ⦟C = 180 degrees, ⦟A=180- ( ⦟C+ ⦟B)= 180 – (111.33 + 12.25)=56.42 degrees, By using law of sine, \frac{AB}{sinC} = \frac{BC}{sinA}, AB= \frac{BCsinC}{sinA}=\frac{361sin12.25}{sin56.42}, AB= 91.87

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